Get submitted button's name in Sveltekit actions

I've got a form with 2 buttons:

<form method="POST" class="pt-10"><div class="flex flex-row pt-10"><button type="submit" name="save-and-exit" class="btn btn-primary btn-lg">{ mode == "new" ? "Save and Exit" : "Update and Exit" }</button></div><div class="flex flex-row pt-10"><button type="submit" name="add-tracks" class="btn btn-primary btn-lg">{ "-> Tracks" }</button></div></form>

Omitting the fields in form for simplicity.

My action looks like this:

export const actions = {    default: async ({ request, fetch }) => {        // create API instance        const recordAPI = new RecordAPI(fetch);        // retrieve the data from the form        const data = Object.fromEntries(await request.formData());        // validate data and create DTO        const record = recordDTO(data);        // if errors returned from building the DTO (validation errors) then return the object.        if (record?.errors && !emptyObject(record.errors)) {            return {"data": record.data,"errors": record.errors,            };        }        // save the data        const response = await recordAPI.post(record);        if (response.status == 200) {            throw redirect(302, '/records')        }        return {            data: record,"errors": response.errors,        }}

In the action function, is there a way to know which of the 2 buttons was the one that submitted the form? I need to know this since the flow is gonna be different depending on that.

One solution I can think of is updating the form to something like this:

<form method="POST" bind:this={formElement}>

then manually append the name of the button to the form and trigger formElement.requestSubmit(), but I was wondering if there's a way to do it directly in the action, I believe it looks more 'elegant'.

Thanks.